Consider two objects A and B. What will happen to the value of G involved in calculating the gravitational force between two objects if: (i) sides of the object are doubled. (ii) both are inverse in water. (iii) both are placed in vacuum
Answers
Answer:
Gravitational force F=
r
2
Gm
1
m
2
Case (i) : Mass of one object is doubled i.e m
1
′
=2m
1
∴ F
′
=
r
2
G(2m
1
)m
2
⟹F
′
=2F
Thus gravitational force gets also doubled
Case (ii) : Distance between the objects is doubled i.e r
′
=2r
∴ F
′
=
(2r)
2
Gm
1
m
2
⟹F
′
=
4
F
Thus gravitational force gets reduced by 4 times.
Distance between the objects is tripled i.e r
′
=3r
∴ F
′
=
(3r)
2
Gm
1
m
2
⟹F
′
=
9
F
Thus gravitational force gets reduced by 9 times.
Case (iii) : Mass of both the objects are doubled i.e m
1
′
=2m
1
and m
2
′
=2m
2
∴ F
′
=
r
2
G(2m
1
)(2m
2
)
⟹F
′
=4F
Thus gravitational force becomes 4 times
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