Question

Consider two particles (A & B) in a cathode ray tube. Particle A pushes off two seconds ahead

of particle B with 50m left to reach
the target. If particle A travels at an average speed of 1.9m/sec

and particle B travels at an average speed of 2.1 m/sec, which particle wins the race? How far

ahead in seconds and meters is the winning particle? Use SI units only​

Answer 1

Answer:

B will win in the race

Explanation:

B will win in the race because it's average speed is 2.1m/s which is more than A