Question

Consider two point charges which are same magnitude and oposite in having magnitude q and the distance between charges in 2a


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Answer 1

Explanation:

Distance between 4q and q=

2/x

Distance between q and Q=x−

2/x

=

2/x

F

1

= Force between 4q and q

=k×

(

2

x

)

2

4q

2

=

x

2

16kq

2

F

1

= Force between q and Q

=k×

(

2

x

)

2

qQ

=

x

2

4kqQ

Net force =0

i.e, F

1

+F

2

=0

x

2

16kq

2

+

x

2

4kqQ

=0

x

2

16kq

2

=−

x

2

4kqQ

q=

4

−Q

i.e, Q=−4q