Consider two point charges which are same magnitude and oposite in having magnitude q and the distance between charges in 2a
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Explanation:
Distance between 4q and q=
2/x
Distance between q and Q=x−
2/x
=
2/x
F
1
= Force between 4q and q
=k×
(
2
x
)
2
4q
2
=
x
2
16kq
2
F
1
= Force between q and Q
=k×
(
2
x
)
2
=
x
2
4kqQ
Net force =0
i.e, F
1
+F
2
=0
x
2
16kq
2
+
x
2
4kqQ
=0
x
2
16kq
2
=−
x
2
4kqQ
q=
4
−Q
i.e, Q=−4q
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