Question

Consider two vectors A and B and their magnitudes are given as
|A|= 3 units; [B]=6 units
The angle between vectors A and B is 30°. The value of |A-B] will be :​

Answer 1

Answer:

Let the two vectors be P and Q and their resultant vector be R.

Let the angle between P and Q be θ.

Given: ∣P∣=3, ∣Q∣=4 and ∣R∣=5 units

Magnitude of resultant vector ∣R∣

2

=∣P∣

2

+∣Q∣

2

+2∣P∣∣Q∣cosθ

∴ 5

2

=3

2

+4

2

+2(3)(4)cosθ

We get cosθ=0

⟹θ=90

o

Answer 2

Answer:

-3= 6- 3

A-B -- 3-6

= -3

Therefore ans is minus three