Consider X, molecules for which X = B, C, N, O and F. Which of the following observations provides
experimental evidence for the so-called o-n crossover?
Select one:
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Q. Consider X₂ molecule for which X = B, C, N, O and F. Which of the following observations provides experimental evidence for the so-called σ-π crossover?
a) N₂ is diamagnetic
b) F₂ is diamagnetic
c) B₂ is paramagnetic
d) O₂ is paramagnetic
ANSWER:
B₂ is paramagnetic.
EXPLANATION:
- B₂ molecule is formed by overlapping of 2 boron atom.
- two boron atom are bonded by covalent bond.
- Energy level of boron molecule= { (σ2s)² (σ*2s)² (π2px)¹ (π*2py)¹.
- Boron has one 2s orbital and three 2p orbital.
- The 2s orbital will overlap and form 2sσ and 2sσ* orbitals.
- 2px orbital will overlap and will form 2pσ and 2pσ* orbital.
- 2py and 2pz will overlap to form pairs of 2pπ and 2pπ*.
- The order of energy will be :
2sσ < 2sσ* < 2pπ < 2pσ <2pπ* < 2pσ*
- no. of antibonding orbital = 2 and bonding orbital = 4, therefore Bond order = 1
- Since (π2px) and (π*2py) has unpaired electron therefore B₂ is paramagnetic.
CONCLUSION
option (c). B₂ is paramagnetic is correct.
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