Question

Consider Y(x)= 2x^3+6x^2+3x. Identify the critical values and verify if it gives maxima or minima.
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Answer 1

Answer:

Critical points : $x = -1-\frac{1}{\sqrt{2} } , -1+\frac{1}{\sqrt{2} }$

Maximum value exists at $x = -1-\frac{1}{\sqrt{2} }$

Minimum value exists at $x = -1+\frac{1}{\sqrt{2} }$

Step-by-step explanation: