Question

consider Z7 under +z . compute (6)^-1 ​

Answer 1

Answer:

Find the multiplicative inverse of each nonzero element of Z7. Solution: Since 6 ≡ −1 (mod 7), the class [6]7 is its own inverse. Furthermore, 2 · 4=8 ≡ 1 (mod 7), and 3 · 5 = 15 ≡ 1 (mod 7), so [2]7 and [4]7 are inverses of each other, and [3]7 and [5]7 are inverses of each other.

Step-by-step explanation:

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