considered the number 4 n where n is a natural number check whether there is any value of n for which 4 and ends with the digit 0?
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This means that the prime factorisation of 4n should contain the prime number 5. But it is not possible because 4n=(2)2n so 2 is the only prime in the factorisation of 4n. Since 5 is not present in the prime factorization, so there is no natural number n for which 4n ends with the digit zero.
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