Question

Considering a system having two masses m, and m, in which first mass is pushed towards centre of mass by
a distance a, the distance required to be moved for second mass to keep centre of mass at same position is
mo
ka
-0m₂
ma
(A) m₂
(B) mm,
(c) ma
(D)
mm,)
m, + m
​

Answer 1

Answer: m1.a/ m2

Explanation: let's make the momentum conserved. Take distance moved by m2 be b.

m1v1=m2v2

m1.a/t=m2.b/t

m1.a=m2.b

m1.a/m2=b