Question

Considering the given reaction: PbO+2HCI--->PbCl2+H2O
How many moles of lead (II) chloride will be formed from a
reaction between 6.5 g of PbO and 3.2 g of HCI?

0.044

0.333

0.011

0.029​

Answer 1

Answer:

ANSWER

PbO+2HCl→PbCl

2

+H

2

O

Atomic mass of PbO = 207 + 16 = 223

Atomic mass of HCl = 36.5

Moles of PbO =

223

6.5

= 0.029 moles

Moles of HCl =

36.5

3.2

= 0.088 moles

From the above chemical equation, we see that PbO is the limiting reagent.

∴ 1 mole of PbO gives 1 mole of PbCl

2

0.029 moles of PbO forms 0.029 moles of PbCl

2

.option is D