Question

Considering the reaction
N2 + 3H2 + 2NH3
If 30 dm' of each reactant react together then the
volume of the mixture at the end is

Answer 1

ANSWER

ANSWERN2+3H2→2NH3

ANSWERN2+3H2→2NH3−dtd[H2]=0.3×10−4Ms−1

ANSWERN2+3H2→2NH3−dtd[H2]=0.3×10−4Ms−1Rate =31dt−d[H2]=+21dtd[NH3]

ANSWERN2+3H2→2NH3−dtd[H2]=0.3×10−4Ms−1Rate =31dt−d[H2]=+21dtd[NH3]=dtd[NH3]=32dt−d[H2]

ANSWERN2+3H2→2NH3−dtd[H2]=0.3×10−4Ms−1Rate =31dt−d[H2]=+21dtd[NH3]=dtd[NH3]=32dt−d[H2]=dtd[NH3]=3−2×(0.3×10−4)

ANSWERN2+3H2→2NH3−dtd[H2]=0.3×10−4Ms−1Rate =31dt−d[H2]=+21dtd[NH3]=dtd[NH3]=32dt−d[H2]=dtd[NH3]=3−2×(0.3×10−4)dtd[NH3]=−0.2×10−4Ms

Answer 2

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