Question

Considering VSEPR and find number of
molecule(s) in which two "O" atoms are present
at 180° angle (linear position)
03. CO2, SO,C1, Xe0,F2, XeO,F, Xeo,​

Answer 1

Answer:

Chlorine trifluoride has 10 electrons around the central chlorine atom. This means there are five electron pairs arranged in a trigonal bipyramidal shape with a 175° F−Cl−F bond angle. There are two equatorial lone pairs making the final structure T−shaped.

Explanation:

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Answer 2

In CO₂ the  two "O" atoms are present  at 180° angle.

• CO₂ has a total of 6+8+8 electrons = 22 electrons.
• Out of 22 electrons, the number of valence electrons is 4+6+6 = 16
• We know that oxygen forms double bonds to attain octet and since there are two oxygen atoms, the total number of bonds = 2X 2= 4
• Number of bonded electrons = Number of bonds X 2 = 4 X 2 =8
• Number of lone electrons = 16 - 8 = 8
• Number of lone pairs= 8/2 =4
• Hence, carbon dioxide has 4 pairs of lp and 4 pairs of bp. The 4 lp are on the two oxygen atoms.
• Since there is no lp on the central atom, the structure of CO₂ is linear.