Question

consrtut a triangle PQR in which PQ=5cm,angle Q=50 degrees,angle R=105 degrees

Answer 1

Steps:

First draw a line segment of 5 centimetre then name it as a b and then at point a construct an angle of 50 degree then then construct half of 50 degree equals to 25 then similarly at point B construct an angle of 105 degree and make half of angle of it equal to 52 and half then where they intersect name that point p then draw a perpendicular bisector of AP and then perpendicular bisector of BP where they meet at a b line segment name that point Q and R hence pqr is your required Triangle.