Consruct a quadrilateral ABCD in which angleB= 80degree
angleA= 120 degree
AB = 3.6 cm
BC= 4 cm
AD = 5 cm
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⇒ Draw a line segment AB = 5cm.
⇒ With A as a center and radius AC = 5cm, draw an arc.
⇒ With B as a center and radius BC = 6cm, draw an arc, intersecting the previous arc at point C.
⇒ With A as a center and radius AD = 3cm, draw an arc.
⇒ Take C as a center with radius CD = 4cm draw an arc intersecting the previous arc at point D.
⇒ Join AC, BC, AD and CD.
Thus, ABCD is a required quadrilateral.
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