Physics, asked by snehal3017, 1 year ago

constant force acting on a body of mass 3kg changes its from 2m/s to 4m/s in 1 second calculate the acceleration and the force acting on the body​

Answers

Answered by VishalSharma01
160

Answer:

Explanation:

Given :-

Mass (m) = 3 kg

Initial velocity (u) = 2 m/s

Final velocity (v) = 4 m/s

Time (t) = 1 s

To Find :-

Force acting

Formula to be used :-

v = u + at

F = ma

Solution :-

Putting all the value, we get

v = u + at

⇒ 4 = 2 + a × 1

⇒ a = 2 m/s²

Now, we will find force

F = ma

⇒ F = 3 × 2

F = 6 N

Hence, the force acting on body is 6 N.

Answered by SharmaJee
20

Answer:

Explanation:

Solution :-

V = u + at

4 = 2 + a(1)

a = 2 m/s

F = ma

F = 3 * 2

F = 6 N

Hence, force acting on body is 6 N.

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