constant forces F1=2i-5j+6k and F2=-i+2j-k are acting on a particle. determine the particle is displaced from point A(4i-3j-2k) to point B(6i+j-3k).
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Step-by-step explanation: displacement from point A to point B is
= 6i+j-3k - ( 4i-3j -2k)
= 2i +4j -k
total force = 2i-5j+6k + (-i+2j-k)
= i-3j+5k
work done = force x displacement
= i-3j+5k x 2i+4j-k we know that cross product of two vector
= -17i +11j+10k
ans : -17i+11j+10k
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