Math, asked by suraj50401, 2 months ago

Constant term in the expansion of sin x

in power of x​

Answers

Answered by tias52052
0

Answer:

This is your answer

may this will help you

Attachments:
Answered by shritik1605sl
0

Answer:

The constant term in the expansion of sin x is given as  \sum\frac{(-1)^n}{(2n+1)!}

where n belongs to whole number.

Step-by-step explanation:

The maclaurin expansion of any function is defined as the infinite polynomial expansion of the function with its derivatives as the coefficient of terms in polynomial.

The Maclaurin expansion of sin x is given as

                                    sin \ x = x-\frac{x^3}{3!}+\frac{x^5}{5!}-\frac{x^7}{7!}+.....

Therefore from the above expression we can clearly express the constant term in multiplication with x as      

                                    \sum\frac{(-1)^n}{(2n+1)!}

where n belongs to whole number.

Similar questions