Question

constant term of polynomial p(x)=x^2-5x-7​

Answer 1

Answer:

$p(0) = {0}^{2} - 5(0) - 7 \\ = - 7 \\ \\ p(1) = {1}^{2} - 5(1) - 7 \\ = 1 - 5 - 7 \\ = - 4 - 7 \\ = - 11 \\ \\ p( - 1) = { - 1}^{2} - 5( - 1) - 7 \\ = 1 + 6 - 7 \\ = 7 - 7 \\ = 0$

Answer 2

Answer:

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Step-by-step explanation:

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