Constract an equilaterl tringle whose attitude measures 5.5 cm
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Then cut off DZ at A with an arc of radius = 5.5 cm (altitude given). Draw the perpendicular bisector FEG of DA using arcs from D and A on both sides. Now with D as the center and DE as the radius draw a semicircle. Now with CE as the radius and E as the center, cut off the semicircle at H and I.
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Answer:
(5.5)^2+x^2=(2x)^2
30.25+x^2=4x^2
30.25/3=x^2
10.08=x^2
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