constract nfa for the regular language 0^+ 1^+
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To construct a DFA M = (Q′, Σ,δ′,q′. 0. ,F′) that is equivalent to NFA N, first we compute the ε-closure of every subset of Q = {1, 2, 3}. Set R ⊆ Q ε-closure E(R). ∅.
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