Question

Construc a triangle with sides 4cm, 5cm, 6cm. Now construct another triangle are 3by 5 times the corresponding sides of the given triangle

Answer 1

1 ) let ABC be the triangle where BC is 6cm put the rounder on point B and then make an arc of 4cm now put the rounder on point C and taking the measure of 5cm intersect the previous arc..
2 ) from point B make Ray below BC take any measure In the rounder and mark point B1 B2 B3 B4 B5 on that ray such that B1=B2=B3=B4=B5
3 ) join B5C . now construct an angle congruent to angle BB5C at point B3
4 ) draw seg B3Q parallel to B5C.
5) now construct an angle congruent to angle ACB at point Q .
6) draw seg PQ parallel to AC .
7) here triangle PBQ is the required triangle