Math, asked by mistryomprakash747, 6 hours ago

Construct 2 equation starting with X = 5.​

Answers

Answered by Badboy330
232

GIVEN:-

x = 5

 \bf \color{red}=>SOLUTION

 \bf \color{black}Multipllying \:  both \:  sides \:  by \\  = 5 \times 5x = 25

\bf \color{black}Adding \:  6  \: on \:  both  \: sides,  \\  5x + 6 = 25 + 6 =  &gt;5x + 6 = 31</p><p></p><p></p><h2>HENCE:-</h2><p></p><p>[tex]\bf \color{green}5x = 25 \: and \: 5x + 6 = 31 \\ are \: the \: required \: equations.

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Answered by anuragkumar8432rupdi
0

Step-by-step explanation:

GIVEN:-

x = 5x=5

\bf \color{red}= > SOLUTION=>SOLUTION

\begin{gathered} \bf \color{black}Multipllying \: both \: sides \: by \\ = 5 \times 5x = 25\end{gathered}

Multipllyingbothsidesby

=5×5x=25

\begin{gathered}\bf \color{black}Adding \: 6 \: on \: both \: sides, \\ 5x + 6 = 25 + 6 = > 5x + 6 = 31 < /p > < p > < /p > < p > < /p > < h2 > HENCE:- < /h2 > < p > < /p > < p > [tex]\bf \color{green}5x = 25 \: and \: 5x + 6 = 31 \\ are \: the \: required \: equations.\end{gathered}

Adding6onbothsides,

5x+6=25+6=>5x+6=31</p><p></p><p></p><h2>HENCE:−</h2><p></p><p>[tex]5x=25and5x+6=31

aretherequiredequations.

\huge\underline{\colorbox{pink}{BE BRAINLY}}

BE BRAINLY

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