Question

Construct a 3*4 matrix whose element are aij=I/j

Answer 1

Answer:

aij = a(number of rows = i) x (number of columns = j)

a₁₁ = 1                     a₂₁ = 2                     a₃₁ = 3                a₁₄ = 0.25

a₁₂ = 1/2 = 0.50     a₂₂ = 1                     a₃₂ = 1.50           a₂₄ = 0.50

a₁₃ = 1/3 = 0.34     a₂₃ = 2/3 = 0.67     a₃₃ = 1                 a₃₄ = 0.75

Therefore, 3x4 Matrix is :

$\left[\begin{array}{cccc}1&0.50&0.34&0.25\\2&1&0.67&0.50\\3&1.50&1&0.75\end{array}\right]$