Question

Construct a 3x4 malrin whose elements aij= i+j​

Answer 1

Answer:

[2 3 4 5]

[3 4 5 6]

[4 5 6 7]

Answer 2

Answer:

$\sf A = \left [ \begin {array} {cccc}2 & 3 & 4 & 5 \\ 3 & 4 & 5 & 6 \\ 4 & 5 & 6 & 7 \end {array} \right]$

Step-by-step explanation:

$\sf a_{11} = 1 + 1 = 2$

$\sf a_{12} = 1 + 2 = 3$

$\sf a_{13} = 1 + 3 = 4$

$\sf a_{14} = 1 + 4 = 5$

$\sf a_{21} = 2+ 1 = 3$

$\sf a_{22} = 2+ 2 = 4$

$\sf a_{23} = 2 + 3= 5$

$\sf a_{24} = 2 + 4 = 6$

$\sf a_{31} = 3 + 1 = 4$

$\sf a_{32} = 3 + 2= 5$

$\sf a_{32} = 3 + 2 = 5$

$\sf a_{33} = 3 + 3 = 6$

$\sf a_{34} = 3 + 4 = 7$

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