Construct a 4 ABC in which AB = 4 cm, BC = 3 cm and AC = 5 cm. Measure <B.
What type of triangle is this?
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Step-by-step explanation:
Given
BC=3 cm
AC=4 cm and
AB=5 cm
Steps of Construction:
(i) Draw a line segment AB of length 5 cm
(ii) From B, using compass cut an arc of 3 cm radius
(iii) Similarly, from A again with the help of a compass, cut an arc of 4 cm bisecting the previous arc formed from point B
(iv) Now, join point C with A and B
(v) The obtained triangle is the required ΔABC
(vi) On measuring ∠ACB, we get ∠ACB=90
0
.
Therefore, the obtained triangle ABC is a right-angled triangle
hope it will help you
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