Math, asked by alaa17, 10 months ago

Construct a 95% confidence interval for the effect of years of education on log weekly earnings.​

Answers

Answered by Anonymous
2

Step-by-step explanation:

<body bgcolor=yellow><marquee><font color=Red>

Let the Values...as Follow :-

X1: Years of education

X2: Experience Years

X3: Square of Experience Years

The statistical equation is assumed:

log(earnings)i=4.016(0.222)+0.092(0.008)X1+0.079(0.025)X2−0.002(0.001)X30.092:Mean(0.008):StandardDeviationFormula,X±Z(s)log(earnings)i=4.016(0.222)+0.092(0.008)⁡X1+0.079(0.025)⁡X2−0.002(0.001)⁡X30.092:Mean(0.008):StandardDeviationFormula,X±Z(s)

Using the statistical table, the value of 95% confidence interval will be 1.96

CI=[0.092−1.96×0.008,0.092+1.96×0.008]

CI=[0.07632,0.10768]

_____________________________________________

..Marks As Brainlist.....

Take Care.....

# Indians Fight Against Corona....

\huge\underline\mathfrak \ </strong><strong>{</strong><strong>THANKS</strong><strong>}

Similar questions