Construct a A ABC in which BC = 3.6 cm, AB+ AC = 4.8 cm and 2B = 60°
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Steps of Construction:
=> Step 1: Draw a line segment BC = 3.6 cm.
=> Step 2: At the point B, draw ∠XBC = 60°.
=> Step 3: Draw an arc which intersects XBa at point D form point B and with radius 4.8 cm
=> Step 4: Join DC.
=> Step 5: Draw a perpendicular bisector of DC which intersects DB at A.
=> Step 6: Join AC.
Hence, △ABC is the required triangle.
Step-by-step explanation:
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