Math, asked by sonukd087212ad1, 9 months ago

Construct a AABC in which BC=8cm, (B-45° and AB-AC-2.5cm​

Answers

Answered by shivangkumar8banshul
1

Step-by-step explanation:

Step I: Draw the line segment BC = 8 cm and at point B, make an angle of 45°, say ∠XBC.

Step II: Cut the line segment BD = 3.5 cm (equal to AB − AC) on ray BX.

Step III: Join DC and draw the perpendicular bisector PQ of DC.

Answered by picachu2005
0
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