Math, asked by ssgin2000, 5 months ago

Construct a AABC whose perimeter is 14 cm and sides are in the ratio 2:2:3.​

Answers

Answered by srirammeghana
1

Answer:

1. Draw Q

R

=14cm

2. Then divide Q

R

in the ratio 2:4:5

3. Q

Q:QR:RR

=2:4:5

4. Now construct PQ=Q

Q

5.Now construct PR=R

R

6. Hence PQ:QR:RP=2:4:5

7. △PQR is the requires triangle.

solution

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Answered by hassanmushtaq
0

Step-by-step explanation:

Let the sides be 2x, 3x and 4x.

now, given that

perimeter of the triangle=14 cm

We know that

perimeter of a triangle= AB + BC + CA units

so, 14= 2x + 3x + 4x

14=9x

x = 14/ 9

Now, the sides of the triangle are

2x=2x14/9 = 28/9 = 3.1 cm

3x = 3x14/9= 14/3 = 4.6 cm

4x = 4x14/9 = 6.2 cm !!

Therefore the sides of the triangle ABC are

3.1 cm, 4.6 cm, 6.2 cm.

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