Construct a AABC whose perimeter is 14 cm and sides are in the ratio 2:2:3.
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Answer:
1. Draw Q
′
R
′
=14cm
2. Then divide Q
′
R
′
in the ratio 2:4:5
3. Q
′
Q:QR:RR
′
=2:4:5
4. Now construct PQ=Q
′
Q
5.Now construct PR=R
′
R
6. Hence PQ:QR:RP=2:4:5
7. △PQR is the requires triangle.
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Step-by-step explanation:
Let the sides be 2x, 3x and 4x.
now, given that
perimeter of the triangle=14 cm
We know that
perimeter of a triangle= AB + BC + CA units
so, 14= 2x + 3x + 4x
14=9x
x = 14/ 9
Now, the sides of the triangle are
2x=2x14/9 = 28/9 = 3.1 cm
3x = 3x14/9= 14/3 = 4.6 cm
4x = 4x14/9 = 6.2 cm !!
Therefore the sides of the triangle ABC are
3.1 cm, 4.6 cm, 6.2 cm.
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