Construct a ∆ ABC
BC=7CM,Angle B= 75°
AB+AC=13CM
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Step-by-step explanation:
Steps of Construction
(iii) From ray BY, cut-off line segment BD = AB + BC = 13cm. (iv) Join CD. (v) Draw the perpendicular bisector of CD meeting BY at A. (vi) Join AC to obtain the required triangle ABC.
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