construct a ∆ABC.Given angle is 60° , angle B=30° ,AB=5.8cm
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how to construct triangle in answer sorry I don't know
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To construct: Δ ABC where m∠ A = 60° , m∠B = 30° and AB = 5.8 cm. Steps of construction: (a) Draw a line segment AB = 5.8 cm. (b) At point A, draw an angle ∠ YAB = 60° with the help of compass. (c) At point B, draw ∠ XBA = 30° with the help of compass. (d) AY and BX intersect at the point C. It is the required triangle ABC.
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