Question

Construct a ∆ABC if it is given that AB = 6cm,m∠CAB = 60° and m∠ABC = 105°.


plz give me ​

Answer 1

Answer:

hey friend I can instead explain you .

Step-by-step explanation:

See first you have to draw AB as your base and then you need to take compass , then keep the pointed end of compass of A then construct an angle of 60° and in the same way by keeping your compass of B construct another angle on B OF 105°. Then just join the lines your triangle will be ready

Answer 2

$\huge \fbox{Answer}$

$\large \underline {\red {\frak{Step \: of \: construction:}}}$

${ \mapsto{ \sf{Draw \: a \: line \: segment \: AB \: measure \: of \: 6cm.}}}$

${ \mapsto \sf{From \: point \: A, \: draw \: an \: angle \: of \: 60°}} \\ \sf{and \: mark \: the \: ray \: {{XA}}. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

${ \mapsto \sf{From \: point \: B, draw \: an \: angle \: of \: 105°.}} \\ \sf{and \: mark \: the \: ray \:X'B. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

${ \mapsto \sf{Mark \: the \: point \: C \: where \: the \: \angle XAB \: and }} \\ \sf{ \angle X'BA \: is \: intersect . \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

${\mapsto \sf{Hence, \triangle ABC \: is \: required \: triangle.}}$