Construct a ∆ abc in which ab=5 cm a∠45° and bc+ac=5cm.
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Answered by
1
Answer:
the other side can be a we will be 5 cm AC will be 3 cm and BC can be to cm and angle a will be 45 degree also
Answered by
3
Step-by-step explanation:
first draw lineab
then draw a line a
t 45°
cut a arc at 5cm on that line
draw line from point b
till cutted arc
label it as p
draw a perpendicular bisector from bp
that bisector intersect at line bp
that point is point c
join point c & b
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