Math, asked by Anonymous, 1 year ago

Construct A ABC in which AB=5 cm,
B = 45° and BC = 6 cm.​

Answers

Answered by IshaanJoshi7
0

Step-by-step explanation:

draw a line AB of 5Cm.Using protracter mark 45. Take a rounder and construct an arch at 6cm away from b. draw a line passing through th angle and which meets the arch.from a draw a line that meets at the bisection point of the arch and line bc.

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