Question

construct a ABC in which AB + AC= 10cm and A = 45 also write the steps​

Answer 1

Answer:

) Draw BC = 8 cm.

(ii) Construct ∠YBC = 45°.

(iii) From ray BY, cut-off line segment BD = 3.5 cm.

(iv) Join CD.

(v) Draw perpendicular bisector of CD intersecting BY at A.

(vi) Join AC to obtain the required triangle ABC.

Justification

As A lies on the perpendicular bisector of CD. Therefore,

AD = AC

Now, BD = 3.5 cm

⇒ AB – AD = 3.5 cm

⇒ AB – AC = 3.5 cm

Hence, △ABC is the required triangle.