Math, asked by kaursehajdeep55, 11 months ago

Construct a ABC in which AB = AC = 4.8 cm and BC = 5.3 cm. Measure ZB and 2C. Draw
AD I BC.​

Answers

Answered by alamshahil819
4

Answer:

Draw a line segment BC = 5.3cm.

2. With B as a center and radius 4.8cm, draw an arc.

3. With C as a center and radius 4.8cm, draw another arc, cutting the previous arc at A.

4. Join AB and AC.

Then, △ABC is the required triangle.

5. When we will measure ∠B and ∠C the angles of triangle by protractor, then the measure of angles are 56

o

and 56

o

respectively.

6. With A as the center and any radius, draw an arc cutting BC at M and N.

7. With M as the center and the radius more than half of MN, draw an arc.

8. With N as the center and the same radius, draw another arc cutting the previously drawn.

9. Join AP, cutting BC at D.

Then, AP ⊥ BC.

Step-by-step explanation:

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