Question

Construct a ∆ ABC in which AB = AC = 7.2 cm, BC = 9 cm.

Answer 1

steps of construction

1.draw a line BC=9cm
2.With B as centre draw an arc radius=7.2cm.
3.With C as centre draw an arc radius=7.2cm.
4.Join AB and AC.
5.ABC is the required triangle.

Answer 2

1) draw BC = 9 c.m.
2) taking B and C as centre draw a arc of 7.2cm
3) be the point of intersection be above the drawn arc A joins to B and C.
this the required triangle