Question

Construct a ∆ABC in which ∠B = 60°, AC + AB = 7.2 cm and BC = 3.5 cm. Also write steps of constructions​

Answer 1

Step-by-step explanation:

1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45

∘

.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

Since AB−AC=3.5cm is positive.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.

Answer 2

Step-by-step explanation:

1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45

Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

Since AB−AC=3.5cm is positive.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.