Construct a ∆ABC in which ∠B = 60°, AC + AB = 7.2 cm and BC = 3.5 cm. Also write steps of construction
Answers
Answer:
Answer
1.Draw base BC of length 8cm
2. Now, let's draw
∠B=
45 ∘
.Let the ray be BX
3.Open the compass to length
AB−
AC=
3.5
cm.
Since
AB−
AC=
3.5
cm is positive.
So, BD will be above line BC
From point B as center, cut an arc on ray BX .
Let the arc intersect BX at D
4.Join CD
5.Now, we will draw perpendicular bisector of
CD
6.Mark point A where perpendicular bisector intersects
BD
7.Join AC
Result:
∴
△ABC
is the required triangle.
Answer: MARK ME BRAINLIEST
Step-by-step explanation:
Answer
1.Draw base BC of length 8cm
2. Now, let's draw
∠B=
45 ∘
.Let the ray be BX
3.Open the compass to length
AB−
AC=
3.5
cm.
Since
AB−
AC=
3.5
cm is positive.
So, BD will be above line BC
From point B as center, cut an arc on ray BX .
Let the arc intersect BX at D
4.Join CD
5.Now, we will draw perpendicular bisector of
CD
6.Mark point A where perpendicular bisector intersects
BD
7.Join AC
Result:
∴
△ABC
is the required triangle.