Question

Construct a ΔABC in which BC=3.4 cm, AB-AC=1.5 cm and ∠B = 45°.

Answer 1

hope. it helps you.........

Answer 2

Constructed the required triangle

•steps of construction

1. Draw BC of length 3.4 cm

2. Make angle of 60° at B and extend the arm of angle

As, AB-AC = 1.5cm

3. Mark 1.5cm and name it as D on extended arm of the angle B

4. Now join CD

5. Draw Perpendicular bisector of CD and let it intersect the extended arm of angle & that point will be point A

6 Required triangle ABC is ready