Question

construct a ∆ABC in which BC-3.6cm, and AC=5.4. Draw department Akola bisector of the side BC.
please write the correct answer otherwise don't need to write aur agar jisne bhi ulta seedha kuch likha toh mein report kar dungi​

Answer 1

Answer:

• draw a line AC=5.4 cm

• *then draw an arc of 5cm from point A and an arc of 3.6cm from point cC

• *the arcs meet each other at a point. ....name the point as B

• *then take little more than half in the line BC and cut an arc in up and down from point B and C

• *this is the required triangle