Question

Construct a ΔABC in which BC = 3.8 cm, B = 45o

and AB + AC = 6.8cm​

Answer 1

Answer:

Construct a triangle ABC in which BC=8 cm,∠B=45o and AB−AC=3.5 cm.

Hard

Answer

R.E.F image 

sol :- Given 

to construct ΔABC, where BC=8cm,∠B=45∘ and AB-AC = 3.5 cm.

Construction steps :-

(i) Firstly draw a line segment BC = 8 cm as a base.

(ii) Now mark ∠B=45∘ and Extend to x.

(iii) Now take a radius of 3.5 cm and draw an arc from B.

(iv) Now join the arc to C and mark it as D .

(v) Now draw ⊥lar bisectors of DC and mark them as 'P' and 'Q'

(vi) Extend the  ⊥lar bisector till 'X' and mark it as 'A' now join 'C' to 'A'. 

(vii) Now, ΔABC is formed which is required.

(viii) Now , just by considering 1/2 of the radius and the angle make the axis and join them form 'B'

conclusion :-

Thus required Δ ABC with AB-AC = 3.5 cm ∠B=45∘ and BC = 8 cm is constructed.



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