Question

Construct a ∆ ABC in which BC=3.8cm, angle B=45° and AB+AC=6.8cm

Answer 1

Answer:

Step-by-step explanation: please see the answer mentioned below

Answer 2

Construction of ∆ABC is attached.

Given:

• BC=3.8cm, angle B=45° and,
• AB+AC=6.8cm

To find:

• Construction of ∆ABC.

Solution:

Steps of construction:

1. Draw line CB of 3.8 cm with the help of pencil.
2. Draw $\angle XBC=45^{\circ}$ with the help of compass.
3. Mark an arc of radius 6.8 cm on ray XB. Let the point is L.
4. Draw line segment LC.
5. Draw perpendicular bisector of LC, it meets XB at a point, let the point is A.
6. Draw line AC, Thus construction of ∆ABC is complete.

Verification:

On measurement of sides of ∆ABC, it is found that

AB= 3.8 cm

AC= 3 cm

Thus,

AB+AC= 6.8 cm

Learn more:

1) construct triangle abc in which ab= 5.8 cm,bc+ca=8.4cm amd b=60%. plz send pics also

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2) Construct a triangle PQR in which QR = 4.6 cm, Q= 45° and PQ+PR = 8.2 cm.

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