Question

Construct a ∆ ABC in which BC = 4.5 cm , ∆ B = ∆ C = 50° . measures AB and AC . What do you conclube?

Answer 1

Step-by-step explanation:

Sum of the interior angles of a triangle is 180°

∆ B = 50°

∆ C = 50°

∆ A =?

∆ A + ∆ B + ∆ C = 180°

=> ∆ A + 50 + 50 = 180

=> ∆ A = 80°

Now using sine rule we can find the length b and c of the triangle.

a/sin( ∆ A) = b/sin( ∆ B) = c/sin( ∆ C)

a = 4.5cm

4.5/sin(80°) = c/sin(50°)

=> c = 4.5 * sin(50°)/sin(80°) = 3.4cm

Similarly,

4.5/sin(80°) = b/sin(50°)

=> b = 4.5 * sin(50°)/sin(80°) = 3.4cm