Construct a ΔABC in which BC = 4.8 cm, ∠B
= 45° and ∠C = 75°. Measure ∠A
Answers
Step-by-step explanation:
Steps of Construction: Construct a line segment BC = 4.8cm
Considering B as centre and any radius, construct an arc which intersects BC at point P
Considering P as centre and same radius, construct an arc which intersects the previous arc at the point Q
Considering Q as centre and same radius, construct an arc which intersects the arc in step 2 at the point R
Considering R and Q as centres and radius more than half of RQ, construct arcs intersecting each other at the point S
Join BS which intersects the arc in step 2 at the point G so ∠SBC = 90degree
Considering P as centre and radius more than half of PG, construct an arc
Considering G as centre and same radius, construct an arc which intersects the previous arc at the point X
Join B and extend it so ∠B = 45o
Draw ∠TCB = 90o
Considering M and H as centres and radius more than half of MH, construct arcs which intersect each other at point Y
Join CY and extend it so ∠C = 75degree
BX and CY intersects at point A after extending
So, △ ABC is the required triangle
Therefore, ∠A = 60degree