Question

Construct a ΔABC in which BC = 5.6cm, ∠B = 30° and AB - AC = 3cm. Also write the
steps of construction. with image

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$Construct \: \: \: a \: \: \: ΔABC \: \: \: \: in \: \: \: which \: \: \: BC = 5.6cm, \: ∠B = 30° \: \: and \: \: AB - AC = 3cm.$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

1.Draw a line BC=5.6 with the help of ruler

2.Make an angle of 30° on B with the help of compass/protector.

(const. 0°+60°)

3.Extend the line and name it A.

4.Now take a compass cut some length and measure the line BA.

5.Increase the arc of compass and put the needle on C and cut the line BA

and hence ur required triangle is obtained.

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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Answer 2

Answer:

1.Draw a line BC=5.6 with the help of ruler

2.Make an angle of 30° on B with the help of compass/protector.

(const. 0°+60°)

3.Extend the line and name it A.

4.Now take a compass cut some length and measure the line BA.

5.Increase the arc of compass and put the needle on C and cut the line BA

and hence ur required triangle is obtained.