Question

construct a ∆ABC in which BC =6 cm, <B = 60° AC-AB=2 cm​

Answer 1

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Step's of construction

(1) Draw BC = 6 cm.

(2) Construct /_ CBX = 60°.

(3) Along BX , set off BP = 9 cm.

(4) Join CP

(5) Draw the perpendicular bisector of CP tp intersect BP at A .

(6) Join AC. Then, ∆ABC is the required triangle.

Answer 2

Answer:

$\huge \: answer$

Steps of construction:-

•Draw BC=6cm

•Construct /_CBX =60°

•Along BX , set off BP =9 cm

•Join line CP

•Draw the perpendicular bisector of CP to intersect BP at A

•Join AC,Then, ∆ABC is the required triangle.

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Do your diagram with the above given formulas.