Question

Construct a ∆ABC IN Which BC =7.2 cm , AC = 8 cm and <c = 100⁰​

Answer 1

Answer:

1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45

∘

.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

Since AB−AC=3.5cm is positive.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

1) Draw a line segment BC=7.2cm.

2) On C construct an angle of 100°

3) cut off AC = 8cm from CX

4) then join the lines

hope it was helpful

Best Regards

Naisha