Question

construct a ∆ABC in which BC=7cm and <B=75° and AB+AC=13cm. Justify it​

Answer 1

Step-by-step explanation:

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A let it be 7 cm. B

ab +a c=13cm

let ab=x

ac=13 -x

Answer 2

STEPS:

1. Construct BC = 7 cm.
2. Construct angle <B = 75
3. Draw BX (where X is a ray)
4. Cut BX at P with the radius 13 cm from B
5. Draw a perpendicular bisector of CP as MN and extend backward till BP (Point at which CP is bisected is Q)
6. Point A is at BP on ray MN.
7. Triangle ABC

JUSTIFICATION:

1. Congruence between trg. APQ and trg. ACQ by SAS
2. AP = AC
3. AP + BA  = 13
4. AC + BA = 13

Hence Proved