Question

Construct a ∆ ABC in which BC=7cm, angle B = 75 degree and AB + AC = 13 cm​

Answer 1

Given :-

• Base BC = 7cm

• Angle B = 75°

• Sum of two sides AB + AC = 12 Cm.

Required :-

• To Construct ∆ ABC

Steps by steps Construction:-

• ⦿ Draw a Ray BX and cut off a line segment BC = 7cm ; from it .

• ⦿ At B ; construct angle YBX = 75°

• ⦿ With B as centre and radius = 12cm ( because AB + AC = 12cm ) Draw on are to meet by at D .

• ⦿ Join CD

• ⦿ Draw perpendicular bisector PQ of CD intersecting BD at A .

• ⦿ Join AC .

Then , ABC is the required triangle .

A lies on perpendicular bisector of CD .

Therefore , AC = AD

==> AB = BD - AD

==> AB = BD - AC

==> AB + AC = BD = 12cm .

which, is true as given .

Answer 2

Answer:

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